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Configuration = 110
cycles = (10 7 1 9 4)(8 5 2 6 3)

a = 1, b = 4, c = 7
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cycles = (10 7)(9 1)(8 2 5 3 6)(4)

a = 2, b = 5, c = 8
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cycles = (10 4)(9 1)(8 6 3)(7)(5)(2)

a = 4, b = 9, c = 10
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cycles = (10 1 4)(9 7 3)(8)(6)(5)(2)

a = 1, b = 4, c = 10
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cycles = (10)(9 6 4)(8)(7)(5)(3)(2)(1)